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SC1045

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Joachim Ansorg edited this page Nov 12, 2021 · 4 revisions

It's not foo &; bar, just foo & bar.

Problematic code:

foo &; bar

Correct code:

foo & bar

Rationale:

Both & and ; terminate the command. You should only use one of them.

Exceptions

None.

Enjoy what I am trying to create as I am the creator

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