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Split StringListNullOperationExpression to specific parts. Ref. #321
Signed-off-by: Jozsef Marton <[email protected]>
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a514465
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I may be wrong about this, but I believe that in the following query:
The parser matches the
IN
inStringOperatorExpression
- but thisIN
is a list rather than string operator.a514465
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You are right;
IN
is only defined for list-typed right-hand sides. We should probably move it into theListOperatorExpression
rule instead.