Prevent double-free strbuf when nsyms is 0 #192
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When nsyms is 0, 'last' will be equal to 'first', and strbuf will not get a new memory buf. But strbuf is not NULL now, because in the last loop, strbuf may get a memory buf allocated by 'calloc', which is only freed in the loop end but not set to NULL. If we don't set strbuf to NULL in such a case, strbuf will be double freed in the following FREEBUF(strbuf) sentence. Signed-off-by: Wang Guanghui <[email protected]>
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When nsyms is 0, 'last' will be equal to 'first', and strbuf will not get a new memory buf. But strbuf is not NULL now, because in the last loop, strbuf may get a memory buf allocated by 'calloc', which is only freed in the loop end but not set to NULL. If we don't set strbuf to NULL in such a case, strbuf will be double freed in the following FREEBUF(strbuf) sentence.