feat: PushJobAgent do not submit failover request if a problem occurs…

… with jobReport

src/DIRAC/WorkloadManagementSystem/Agent/PushJobAgent.py

@@ -270,20 +270,7 @@ def execute(self):
                 # Committing the JobReport before evaluating the result of job submission
                 res = self.jobReport.commit()
                 if not res["OK"]:
-                    resFD = self.jobReport.generateForwardDISET()
-                    if not resFD["OK"]:
-                        self.log.error("Error generating ForwardDISET operation", resFD["Message"])
-                    elif resFD["Value"]:
-                        # Here we create the Request.
-                        op = resFD["Value"]
-                        request = Request()
-                        requestName = f"jobAgent_{jobID}"
-                        request.RequestName = requestName.replace('"', "")
-                        request.JobID = jobID
-                        request.SourceComponent = f"JobAgent_{jobID}"
-                        request.addOperation(op)
-                        # This might fail, but only a message would be printed.
-                        self._sendFailoverRequest(request)
+                    return result
 
                 # Check that there is enough slots locally
                 result = self._checkCEAvailability(self.computingElement)