A simple, stateless, functional mechanism to perform actions repetitively until successful.
This project is currently in "pre-release". While the code is heavily tested, the API may change. Use a tagged version or vendor this dependency if you plan on using it.
That said, this code has been used in production without issue for years, and has been used by some relatively high-profile projects/codebases.
retry.Retry(func(attempt uint) error {
return nil // Do something that may or may not cause an error
})
const logFilePath = "/var/log/myapp.log"
var logFile *os.File
err := retry.Retry(func(attempt uint) error {
var err error
logFile, err = os.Open(logFilePath)
return err
})
if err != nil {
log.Fatalf("Unable to open file %q with error %q", logFilePath, err)
}
logFile.Chdir() // Do something with the file
var response *http.Response
action := func(attempt uint) error {
var err error
response, err = http.Get("https://api.github.com/repos/Rican7/retry")
if err == nil && response != nil && response.StatusCode > 200 {
err = fmt.Errorf("failed to fetch (attempt #%d) with status code: %d", attempt, response.StatusCode)
}
return err
}
err := retry.Retry(
action,
strategy.Limit(5),
strategy.Backoff(backoff.Fibonacci(10*time.Millisecond)),
)
if err != nil {
log.Fatalf("Failed to fetch repository with error %q", err)
}
action := func(attempt uint) error {
return errors.New("something happened")
}
seed := time.Now().UnixNano()
random := rand.New(rand.NewSource(seed))
retry.Retry(
action,
strategy.Limit(5),
strategy.BackoffWithJitter(
backoff.BinaryExponential(10*time.Millisecond),
jitter.Deviation(random, 0.5),
),
)