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kwakrhkr59
approved these changes
Aug 25, 2023
sawoll
approved these changes
Aug 25, 2023
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| int sum(string a) { | ||
| int result = 0; | ||
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| for (int i = 0; i < a.length(); i++) { | ||
| int anum = a[i] - '0';//string to int | ||
| if (anum >= 0 && anum <= 9) { //�����̸� ���� | ||
| result = result + anum; | ||
| } | ||
| } | ||
| return result; | ||
| } |
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자릿수 합 구하는 함수 따로 구현하신 것 너무 좋아요!😍 문자의 숫자 여부를 판별할 때 string헤더의 isdigit 함수를 사용하는 방법도 알아두시면 편리할 것 같습니다.👍👍
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| int asum = sum(a); | ||
| int bsum = sum(b); | ||
| if (asum != bsum) { //(���� ������) �ڸ��� �� ���� �� ���� | ||
| return asum < bsum; | ||
| } |
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if와 return에서 asum과 bsum 대신 sum함수를 바로 호출한다면 더 간결한 코드가 될 수 있을 것 같습니다!😀
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| auto iter = s.find(str); //key�� ���� ���� Ȯ�� | ||
| if (iter != s.end()) { //�����ϸ� cnt 1 ����, (�������� ������ s.end()�� ��ȯ��) | ||
| cnt++; | ||
| } |
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| map<string, int> s; | ||
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| //�Է� | ||
| cin >> n >> m; | ||
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| for (int i = 0; i < n; i++) { //���� S�� map���� ���� | ||
| cin >> str; | ||
| s[str] = value; | ||
| value++; | ||
| } |
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map을 사용해서 문제를 잘 풀어 주셨습니다!😍 샘플 코드 참고하셔서 set으로 푸는 방법도 한 번 알아보시면 좋을 것 같아요~👍
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