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Earth - Jasmine #19

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92 changes: 83 additions & 9 deletions lib/exercises.rb
Original file line number Diff line number Diff line change
@@ -1,19 +1,42 @@

# This method will return an array of arrays.
# Each subarray will have strings which are anagrams of each other
# Time Complexity: ?
# Space Complexity: ?
# Time Complexity: O(n * klog(k)) where n is the number of strings and k is the length of each string.
# Space Complexity: O(n) - using hash to store each word.
# Does having an array as a key increase the space complexity?

def grouped_anagrams(strings)
Comment on lines +4 to 8

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👍

raise NotImplementedError, "Method hasn't been implemented yet!"
# Create a hash table
anagrams = {}
# Keys will be sorted word
# values will be the arrays of words that are anagrams of sorted word.
strings.each do |word|
sorted_word = word.split('').sort.join
if anagrams.has_key?(sorted_word)
anagrams[sorted_word].push(word)
else
anagrams[sorted_word] = [word]
end
end
return anagrams.values
end

# This method will return the k most common elements
# in the case of a tie it will select the first occuring element.
# Time Complexity: ?
# Space Complexity: ?
# Time Complexity: O(nlog(n)) - due to using sort_by
# Space Complexity: O(n) - hash could potentially hold n unique values.
def top_k_frequent_elements(list, k)
Comment on lines +26 to 28

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👍 Very compact and yet readable.

raise NotImplementedError, "Method hasn't been implemented yet!"
return list if list.length == k

frequency = {}
list.each do |val|
if frequency.has_key?(val)
frequency[val] += 1
else
frequency[val] = 1
end
end
return frequency.sort_by.with_index { |k, idx| [-k[1], idx] }.map {|pair| pair[0]}.first(k)
end


Expand All @@ -22,8 +45,59 @@ def top_k_frequent_elements(list, k)
# Each element can either be a ".", or a digit 1-9
# The same digit cannot appear twice or more in the same
# row, column or 3x3 subgrid
# Time Complexity: ?
# Space Complexity: ?
# Time Complexity: O(1) because the grid is a fixed size.
# Space Complexity: O(1) even though we're using multiple hashes it's O(1) because the grid is a fixed size
def valid_sudoku(table)
Comment on lines +48 to 50

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👍

raise NotImplementedError, "Method hasn't been implemented yet!"
return check_row(table) && check_column(table) && check_square(table)
end

# validate that any array won't have any duplicate values
def is_valid(array)
count = Hash.new(0)
array.each do |value|
if value != '.' && count.has_key?(value)
return false
else
count[value] += 1
end
end
return true
end

def check_row(table)
table.each do |row|
unless is_valid(row)
return false
end
end
return true
end

def check_column(table)
9.times do |column|
column_array = []
9.times do |row|
column_array << table[row][column]
end
return false unless is_valid(column_array)
end
return true
end

def check_square(table)
range = (0...3).to_a.map {|num| num * 3}
range.each do |row|
range.each do |column|
sq_array = []
(row...(row + 3)).each do |row_index|
(column...(column + 3)).each do |column_index|
sq_array << table[row_index][column_index]
end
end
return false unless is_valid(sq_array)
end
end
return true
end


2 changes: 1 addition & 1 deletion test/exercises_test.rb
Original file line number Diff line number Diff line change
Expand Up @@ -151,7 +151,7 @@
end
end

xdescribe "valid sudoku" do
describe "valid sudoku" do
it "works for the table given in the README" do
# Arrange
table = [
Expand Down