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Earth - Jasmine #19
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Earth - Jasmine #19
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Original file line number | Diff line number | Diff line change |
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@@ -1,19 +1,42 @@ | ||
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# This method will return an array of arrays. | ||
# Each subarray will have strings which are anagrams of each other | ||
# Time Complexity: ? | ||
# Space Complexity: ? | ||
# Time Complexity: O(n * klog(k)) where n is the number of strings and k is the length of each string. | ||
# Space Complexity: O(n) - using hash to store each word. | ||
# Does having an array as a key increase the space complexity? | ||
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def grouped_anagrams(strings) | ||
raise NotImplementedError, "Method hasn't been implemented yet!" | ||
# Create a hash table | ||
anagrams = {} | ||
# Keys will be sorted word | ||
# values will be the arrays of words that are anagrams of sorted word. | ||
strings.each do |word| | ||
sorted_word = word.split('').sort.join | ||
if anagrams.has_key?(sorted_word) | ||
anagrams[sorted_word].push(word) | ||
else | ||
anagrams[sorted_word] = [word] | ||
end | ||
end | ||
return anagrams.values | ||
end | ||
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# This method will return the k most common elements | ||
# in the case of a tie it will select the first occuring element. | ||
# Time Complexity: ? | ||
# Space Complexity: ? | ||
# Time Complexity: O(nlog(n)) - due to using sort_by | ||
# Space Complexity: O(n) - hash could potentially hold n unique values. | ||
def top_k_frequent_elements(list, k) | ||
Comment on lines
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There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. 👍 Very compact and yet readable. |
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raise NotImplementedError, "Method hasn't been implemented yet!" | ||
return list if list.length == k | ||
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frequency = {} | ||
list.each do |val| | ||
if frequency.has_key?(val) | ||
frequency[val] += 1 | ||
else | ||
frequency[val] = 1 | ||
end | ||
end | ||
return frequency.sort_by.with_index { |k, idx| [-k[1], idx] }.map {|pair| pair[0]}.first(k) | ||
end | ||
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@@ -22,8 +45,59 @@ def top_k_frequent_elements(list, k) | |
# Each element can either be a ".", or a digit 1-9 | ||
# The same digit cannot appear twice or more in the same | ||
# row, column or 3x3 subgrid | ||
# Time Complexity: ? | ||
# Space Complexity: ? | ||
# Time Complexity: O(1) because the grid is a fixed size. | ||
# Space Complexity: O(1) even though we're using multiple hashes it's O(1) because the grid is a fixed size | ||
def valid_sudoku(table) | ||
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There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. 👍 |
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raise NotImplementedError, "Method hasn't been implemented yet!" | ||
return check_row(table) && check_column(table) && check_square(table) | ||
end | ||
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# validate that any array won't have any duplicate values | ||
def is_valid(array) | ||
count = Hash.new(0) | ||
array.each do |value| | ||
if value != '.' && count.has_key?(value) | ||
return false | ||
else | ||
count[value] += 1 | ||
end | ||
end | ||
return true | ||
end | ||
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def check_row(table) | ||
table.each do |row| | ||
unless is_valid(row) | ||
return false | ||
end | ||
end | ||
return true | ||
end | ||
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def check_column(table) | ||
9.times do |column| | ||
column_array = [] | ||
9.times do |row| | ||
column_array << table[row][column] | ||
end | ||
return false unless is_valid(column_array) | ||
end | ||
return true | ||
end | ||
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def check_square(table) | ||
range = (0...3).to_a.map {|num| num * 3} | ||
range.each do |row| | ||
range.each do |column| | ||
sq_array = [] | ||
(row...(row + 3)).each do |row_index| | ||
(column...(column + 3)).each do |column_index| | ||
sq_array << table[row_index][column_index] | ||
end | ||
end | ||
return false unless is_valid(sq_array) | ||
end | ||
end | ||
return true | ||
end | ||
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👍