You signed in with another tab or window. Reload to refresh your session.You signed out in another tab or window. Reload to refresh your session.You switched accounts on another tab or window. Reload to refresh your session.Dismiss alert
{{ message }}
This repository has been archived by the owner on Jul 8, 2020. It is now read-only.
In the case where we have a page before the page which has got the SplitView (for example, we have a SplashScreen page first), if the screen is too tiny, the menu button will appear.
But this menu will not work because the "page" variable will be linked with the SplashScreen page.
In the file "split.js", please change
var page = M.ViewManager.getCurrentPage() || M.ViewManager.getPage(M.Application.entryPage);
With
var page = M.ViewManager.currentlyRenderedPage || M.ViewManager.getCurrentPage() || M.ViewManager.getPage(M.Application.entryPage);
Cheers
The text was updated successfully, but these errors were encountered:
Hi,
In the case where we have a page before the page which has got the SplitView (for example, we have a SplashScreen page first), if the screen is too tiny, the menu button will appear.
But this menu will not work because the "page" variable will be linked with the SplashScreen page.
In the file "split.js", please change
var page = M.ViewManager.getCurrentPage() || M.ViewManager.getPage(M.Application.entryPage);
With
var page = M.ViewManager.currentlyRenderedPage || M.ViewManager.getCurrentPage() || M.ViewManager.getPage(M.Application.entryPage);
Cheers
The text was updated successfully, but these errors were encountered: