isomorphic.py

"""
205. Isomorphic Strings
Easy

Given two strings s and t, determine if they are isomorphic.

Two strings are isomorphic if the characters in s can be replaced to get t.

All occurrences of a character must be replaced with another character while preserving the order of characters. No two characters may map to the same character but a character may map to itself.

Example 1:

Input: s = "egg", t = "add"
Output: true

Example 2:

Input: s = "foo", t = "bar"
Output: false

Example 3:

Input: s = "paper", t = "title"
Output: true

Note:
You may assume both s and t have the same length.

"""

class Solution:
    def isIsomorphic(self, s: str, t: str) -> bool:
        map={}
        for i in range(0,len(s)):
            if s[i] not in map and t[i] not in map.values():
                map[s[i]]=t[i]
            elif s[i] in map and map[s[i]]==t[i]:
                continue
            elif s[i] in map and map[s[i]]!=t[i]:
                return False
            else:
                return False
        print(map)
        return True
print(Solution().isIsomorphic("foo",'bar'))