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more-groupoids.tex
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\input{preamble}
% OK, start here.
%
\begin{document}
\title{More on Groupoid Schemes}
\maketitle
\phantomsection
\label{section-phantom}
\tableofcontents
\section{Introduction}
\label{section-introduction}
\noindent
This chapter is devoted to advanced topics on groupoid schemes.
Even though the results are stated in terms of groupoid schemes, the
reader should keep in mind the $2$-cartesian diagram
\begin{equation}
\label{equation-quotient-stack}
\vcenter{
\xymatrix{
R \ar[r] \ar[d] & U \ar[d] \\
U \ar[r] & [U/R]
}
}
\end{equation}
where $[U/R]$ is the quotient stack, see
Groupoids in Spaces, Remark \ref{spaces-groupoids-remark-fundamental-square}.
Many of the results are motivated by thinking about this diagram.
See for example the beautiful paper \cite{K-M} by Keel and Mori.
\section{Notation}
\label{section-notation}
\noindent
We continue to abide by the conventions and notation introduced in
Groupoids, Section \ref{groupoids-section-notation}.
\section{Useful diagrams}
\label{section-diagrams}
\noindent
We briefly restate the results of
Groupoids, Lemmas \ref{groupoids-lemma-diagram} and
\ref{groupoids-lemma-diagram-pull}
for easy reference in this chapter.
Let $S$ be a scheme.
Let $(U, R, s, t, c)$ be a groupoid scheme over $S$.
In the commutative diagram
\begin{equation}
\label{equation-diagram}
\vcenter{
\xymatrix{
& U & \\
R \ar[d]_s \ar[ru]^t &
R \times_{s, U, t} R
\ar[l]^-{\text{pr}_0} \ar[d]^{\text{pr}_1} \ar[r]_-c &
R \ar[d]^s \ar[lu]_t \\
U & R \ar[l]_t \ar[r]^s & U
}
}
\end{equation}
the two lower squares are fibre product squares.
Moreover, the triangle on top (which is really a square)
is also cartesian.
\medskip\noindent
The diagram
\begin{equation}
\label{equation-pull}
\vcenter{
\xymatrix{
R \times_{t, U, t} R
\ar@<1ex>[r]^-{\text{pr}_1} \ar@<-1ex>[r]_-{\text{pr}_0}
\ar[d]_{\text{pr}_0 \times c \circ (i, 1)} &
R \ar[r]^t \ar[d]^{\text{id}_R} &
U \ar[d]^{\text{id}_U} \\
R \times_{s, U, t} R
\ar@<1ex>[r]^-c \ar@<-1ex>[r]_-{\text{pr}_0} \ar[d]_{\text{pr}_1} &
R \ar[r]^t \ar[d]^s &
U \\
R \ar@<1ex>[r]^s \ar@<-1ex>[r]_t &
U
}
}
\end{equation}
is commutative. The two top rows are isomorphic via the vertical maps given.
The two lower left squares are cartesian.
\section{Sheaf of differentials}
\label{section-differentials}
\noindent
The following lemma is the analogue of
Groupoids, Lemma \ref{groupoids-lemma-group-scheme-module-differentials}.
\begin{lemma}
\label{lemma-sheaf-differentials}
Let $S$ be a scheme.
Let $(U, R, s, t, c)$ be a groupoid scheme over $S$.
The sheaf of differentials of $R$ seen as a scheme over
$U$ via $t$ is a quotient of the pullback via $t$ of the conormal sheaf of
the immersion $e : U \to R$. In a formula: there is a canonical surjection
$t^*\mathcal{C}_{U/R} \to \Omega_{R/U}$. If $s$ is flat, then
this map is an isomorphism.
\end{lemma}
\begin{proof}
Note that $e : U \to R$ is an immersion as it is a section
of the morphism $s$, see
Schemes, Lemma \ref{schemes-lemma-section-immersion}.
Consider the following diagram
$$
\xymatrix{
R \ar[r]_-{(1, i)} \ar[d]_t &
R \times_{s, U, t} R \ar[d]^c \ar[rr]_{(\text{pr}_0, i \circ \text{pr}_1)} & &
R \times_{t, U, t} R \\
U \ar[r]^e &
R
}
$$
The square on the left is cartesian, because if $a \circ b = e$, then
$b = i(a)$. The composition of the horizontal maps is the diagonal
morphism of $t : R \to U$. The right top horizontal arrow is an
isomorphism. Hence since $\Omega_{R/U}$ is the conormal sheaf of the
composition it is isomorphic to the conormal sheaf of
$(1, i)$. By
Morphisms, Lemma \ref{morphisms-lemma-conormal-functorial-flat}
we get the surjection $t^*\mathcal{C}_{U/R} \to \Omega_{R/U}$
and if $c$ is flat, then this is an isomorphism. Since $c$ is a base change
of $s$ by the properties of Diagram (\ref{equation-pull})
we conclude that if $s$ is flat, then $c$ is flat, see
Morphisms, Lemma \ref{morphisms-lemma-base-change-flat}.
\end{proof}
\section{Properties of groupoids}
\label{section-technical-lemma}
\noindent
Let $(U, R, s, t, c)$ be a groupoid scheme.
The idea behind the results in this section is that $s: R \to U$
is a base changes of the morphism $U \to [U/R]$ (see
Diagram (\ref{equation-quotient-stack}).
Hence the local properties of $s : R \to U$ should reflect local
properties of the morphism $U \to [U/R]$.
This doesn't work, because $[U/R]$ is not always an algebraic stack, and
hence we cannot speak of geometric or algebraic properties of
$U \to [U/R]$.
But it turns out that we can make some of it work without even
referring to the quotient stack at all.
\medskip\noindent
Here is a first example of such a result. The open $W \subset U'$ found
in the lemma is roughly speaking the locus where the morphism
$U' \to [U/R]$ has property $\mathcal{P}$.
\begin{lemma}
\label{lemma-local-source}
Let $S$ be a scheme.
Let $(U, R, s, t, c, e, i)$ be a groupoid over $S$.
Let $g : U' \to U$ be a morphism of schemes.
Denote $h$ the composition
$$
\xymatrix{
h : U' \times_{g, U, t} R \ar[r]_-{\text{pr}_1} & R \ar[r]_s & U.
}
$$
Let $\mathcal{P}, \mathcal{Q}, \mathcal{R}$ be properties of morphisms
of schemes. Assume
\begin{enumerate}
\item $\mathcal{R} \Rightarrow \mathcal{Q}$,
\item $\mathcal{Q}$ is preserved under base change and composition,
\item for any morphism $f : X \to Y$ which has $\mathcal{Q}$ there exists a
largest open $W(\mathcal{P}, f) \subset X$ such that $f|_{W(\mathcal{P}, f)}$
has $\mathcal{P}$, and
\item for any morphism $f : X \to Y$ which has $\mathcal{Q}$,
and any morphism $Y' \to Y$ which has $\mathcal{R}$ we have
$Y' \times_Y W(\mathcal{P}, f) = W(\mathcal{P}, f')$, where
$f' : X_{Y'} \to Y'$ is the base change of $f$.
\end{enumerate}
If $s, t$ have $\mathcal{R}$ and $g$ has $\mathcal{Q}$, then
there exists an open subscheme $W \subset U'$ such that
$W \times_{g, U, t} R = W(\mathcal{P}, h)$.
\end{lemma}
\begin{proof}
Note that the following diagram is commutative
$$
\xymatrix{
U' \times_{g, U, t} R \times_{t, U, t} R
\ar[rr]_-{\text{pr}_{12}}
\ar@<1ex>[d]^-{\text{pr}_{02}} \ar@<-1ex>[d]_-{\text{pr}_{01}} & &
R \times_{t, U, t} R
\ar@<1ex>[d]^-{\text{pr}_1} \ar@<-1ex>[d]_-{\text{pr}_0}
\\
U' \times_{g, U, t} R \ar[rr]^{\text{pr}_1} & & R
}
$$
with both squares cartesian (this uses that the two maps
$t \circ \text{pr}_i : R \times_{t, U, t} R \to U$ are equal).
Combining this with the properties of diagram (\ref{equation-pull})
we get a commutative diagram
$$
\xymatrix{
U' \times_{g, U, t} R \times_{t, U, t} R
\ar[rr]_-{c \circ (i, 1)}
\ar@<1ex>[d]^-{\text{pr}_{02}} \ar@<-1ex>[d]_-{\text{pr}_{01}} & &
R
\ar@<1ex>[d]^-{s} \ar@<-1ex>[d]_-{t}
\\
U' \times_{g, U, t} R \ar[rr]^h & & U
}
$$
where both squares are cartesian.
\medskip\noindent
Assume $s, t$ have $\mathcal{R}$ and $g$ has $\mathcal{Q}$.
Then $h$ has $\mathcal{Q}$ as a composition of $s$ (which has
$\mathcal{R}$ hence $\mathcal{Q}$) and a base change of $g$ (which
has $\mathcal{Q}$). Thus $W(\mathcal{P}, h) \subset U' \times_{g, U, t} R$
exists. By our assumptions we have
$\text{pr}_{01}^{-1}(W(\mathcal{P}, h)) =
\text{pr}_{02}^{-1}(W(\mathcal{P}, h))$
since both are the largest open on which $c \circ (i, 1)$ has $\mathcal{P}$.
Note that the projection $U' \times_{g, U, t} R \to U'$ has a section, namely
$\sigma : U' \to U' \times_{g, U, t} R$, $u' \mapsto (u', e(g(u')))$.
Also via the isomorphism
$$
(U' \times_{g, U, t} R) \times_{U'} (U' \times_{g, U, t} R)
=
U' \times_{g, U, t} R \times_{t, U, t} R
$$
the two projections of the left hand side
to $U' \times_{g, U, t} R$ agree with the morphisms $\text{pr}_{01}$
and $\text{pr}_{02}$ on the right hand side. Since
$\text{pr}_{01}^{-1}(W(\mathcal{P}, h)) =
\text{pr}_{02}^{-1}(W(\mathcal{P}, h))$
we conclude that $W(\mathcal{P}, h)$ is the inverse image of a subset of $U$,
which is necessarily the open set
$W = \sigma^{-1}(W(\mathcal{P}, h))$.
\end{proof}
\begin{remark}
\label{remark-local-source-warning}
Warning:
Lemma \ref{lemma-local-source}
should be used with care.
For example, it applies to $\mathcal{P}=$``flat'', $\mathcal{Q}=$``empty'',
and $\mathcal{R}=$``flat and locally of finite presentation''. But given a
morphism of schemes $f : X \to Y$ the largest open $W \subset X$ such that
$f|_W$ is flat is {\it not} the set of points where $f$ is flat!
\end{remark}
\begin{remark}
\label{remark-local-source-apply}
Notwithstanding the warning in
Remark \ref{remark-local-source-warning}
there are some cases where
Lemma \ref{lemma-local-source}
can be used without causing too much ambiguity.
We give a list. In each case we omit the verification of
assumptions (1) and (2) and we give references which imply
(3) and (4). Here is the list:
\begin{enumerate}
\item $\mathcal{Q} = \mathcal{R} =$``locally of finite type'', and
$\mathcal{P} =$``relative dimension $\leq d$''.
See
Morphisms, Definition \ref{morphisms-definition-relative-dimension-d}
and
Morphisms, Lemmas \ref{morphisms-lemma-openness-bounded-dimension-fibres} and
\ref{morphisms-lemma-dimension-fibre-after-base-change}.
\item $\mathcal{Q} = \mathcal{R} =$``locally of finite type'', and
$\mathcal{P} =$``locally quasi-finite''.
This is the case $d = 0$ of the previous item, see
Morphisms, Lemma \ref{morphisms-lemma-locally-quasi-finite-rel-dimension-0}.
\item $\mathcal{Q} = \mathcal{R} =$``locally of finite type'', and
$\mathcal{P} =$``unramified''.
See
Morphisms, Lemmas \ref{morphisms-lemma-unramified-characterize} and
\ref{morphisms-lemma-set-points-where-fibres-unramified}.
\end{enumerate}
What is interesting about the cases listed above is that we do not
need to assume that $s, t$ are flat to get a conclusion about the locus
where the morphism $h$ has property $\mathcal{P}$. We continue the
list:
\begin{enumerate}
\item[(4)] $\mathcal{Q} =$``locally of finite presentation'',
$\mathcal{R} =$``flat and locally of finite presentation'', and
$\mathcal{P} =$``flat''. See
More on Morphisms, Theorem
\ref{more-morphisms-theorem-openness-flatness} and
Lemma \ref{more-morphisms-lemma-flat-locus-base-change}.
\item[(5)] $\mathcal{Q} =$``locally of finite presentation'',
$\mathcal{R} =$``flat and locally of finite presentation'', and
$\mathcal{P}=$``Cohen-Macaulay''. See
More on Morphisms, Definition \ref{more-morphisms-definition-CM}
and
More on Morphisms, Lemmas \ref{more-morphisms-lemma-base-change-CM} and
\ref{more-morphisms-lemma-flat-finite-presentation-CM-open}.
\item[(6)] $\mathcal{Q} =$``locally of finite presentation'',
$\mathcal{R} =$``flat and locally of finite presentation'', and
$\mathcal{P}=$``syntomic'' use
Morphisms, Lemma \ref{morphisms-lemma-set-points-where-fibres-lci}
(the locus is automatically open).
\item[(7)] $\mathcal{Q} =$``locally of finite presentation'',
$\mathcal{R} =$``flat and locally of finite presentation'', and
$\mathcal{P}=$``smooth''. See
Morphisms, Lemma \ref{morphisms-lemma-set-points-where-fibres-smooth}
(the locus is automatically open).
\item[(8)] $\mathcal{Q} =$``locally of finite presentation'',
$\mathcal{R} =$``flat and locally of finite presentation'', and
$\mathcal{P}=$``\'etale''. See
Morphisms, Lemma \ref{morphisms-lemma-set-points-where-fibres-etale}
(the locus is automatically open).
\end{enumerate}
\end{remark}
\noindent
Here is the second result. The $R$-invariant open $W \subset U$ should be
thought of as the inverse image of the largest open of $[U/R]$ over which
the morphism $U \to [U/R]$ has property $\mathcal{P}$.
\begin{lemma}
\label{lemma-property-invariant}
Let $S$ be a scheme.
Let $(U, R, s, t, c)$ be a groupoid over $S$.
Let $\tau \in \{Zariski, \linebreak[0] fppf,
\linebreak[0] \etale, \linebreak[0]
smooth, \linebreak[0] syntomic\}$\footnote{The fact that $fpqc$ is missing
is not a typo.}. Let $\mathcal{P}$ be a property of morphisms of schemes
which is $\tau$-local on the target
(Descent, Definition \ref{descent-definition-property-morphisms-local}).
Assume $\{s : R \to U\}$ and $\{t : R \to U\}$ are coverings for the
$\tau$-topology. Let $W \subset U$ be the maximal open subscheme such that
$s|_{s^{-1}(W)} : s^{-1}(W) \to W$ has property $\mathcal{P}$.
Then $W$ is $R$-invariant, see
Groupoids, Definition \ref{groupoids-definition-invariant-open}.
\end{lemma}
\begin{proof}
The existence and properties of the open $W \subset U$ are described in
Descent, Lemma \ref{descent-lemma-largest-open-of-the-base}.
In
Diagram (\ref{equation-diagram})
let $W_1 \subset R$ be the maximal open subscheme over which the morphism
$\text{pr}_1 : R \times_{s, U, t} R \to R$ has property $\mathcal{P}$.
It follows from the aforementioned
Descent, Lemma \ref{descent-lemma-largest-open-of-the-base}
and the assumption that $\{s : R \to U\}$ and $\{t : R \to U\}$ are coverings
for the $\tau$-topology that $t^{-1}(W) = W_1 = s^{-1}(W)$ as desired.
\end{proof}
\begin{lemma}
\label{lemma-property-G-invariant}
Let $S$ be a scheme.
Let $(U, R, s, t, c)$ be a groupoid over $S$.
Let $G \to U$ be its stabilizer group scheme.
Let $\tau \in \{fppf, \linebreak[0] \etale, \linebreak[0]
smooth, \linebreak[0] syntomic\}$.
Let $\mathcal{P}$ be a property of morphisms which is $\tau$-local
on the target. Assume $\{s : R \to U\}$ and $\{t : R \to U\}$ are coverings
for the $\tau$-topology. Let $W \subset U$ be the maximal open subscheme
such that $G_W \to W$ has property $\mathcal{P}$. Then $W$ is $R$-invariant
(see
Groupoids, Definition
\ref{groupoids-definition-invariant-open}).
\end{lemma}
\begin{proof}
The existence and properties of the open $W \subset U$ are described in
Descent, Lemma \ref{descent-lemma-largest-open-of-the-base}.
The morphism
$$
G \times_{U, t} R \longrightarrow R \times_{s, U} G, \quad
(g, r) \longmapsto (r, r^{-1} \circ g \circ r)
$$
is an isomorphism over $R$ (where $\circ$ denotes
composition in the groupoid). Hence $s^{-1}(W) = t^{-1}(W)$ by the
properties of $W$ proved in the aforementioned
Descent, Lemma \ref{descent-lemma-largest-open-of-the-base}.
\end{proof}
\section{Comparing fibres}
\label{section-fibres}
\noindent
Let $(U, R, s, t, c, e, i)$ be a groupoid scheme over $S$.
Diagram (\ref{equation-diagram})
gives us a way to compare the fibres of the map $s : R \to U$ in a groupoid.
For a point $u \in U$ we will denote $F_u = s^{-1}(u)$ the scheme
theoretic fibre of $s : R \to U$ over $u$. For example the diagram
implies that if $u, u' \in U$ are points such
that $s(r) = u$ and $t(r) = u'$, then
$(F_u)_{\kappa(r)} \cong (F_{u'})_{\kappa(r)}$.
This is a special case of the more general and more precise
Lemma \ref{lemma-two-fibres}
below. To see this take $r' = i(r)$.
\medskip\noindent
A pair $(X, x)$ consisting of a scheme $X$ and a point $x \in X$ is sometimes
called the {\it germ of $X$ at $x$}.
A {\it morphism of germs} $f : (X, x) \to (S, s)$
is a morphism $f : U \to S$ defined on an open neighbourhood
of $x$ with $f(x) = s$. Two such
$f$, $f'$ are said to give the same morphism of germs
if and only if $f$ and $f'$ agree in some open neighbourhood of $x$.
Let $\tau \in \{Zariski, \etale, smooth, syntomic, fppf\}$.
We temporarily introduce the following concept: We say that two morphisms
of germs $f : (X, x) \to (S, s)$ and $f' : (X', x') \to (S', s')$
are {\it isomorphic locally on the base in the $\tau$-topology},
if there exists a pointed scheme $(S'', s'')$ and morphisms of germs
$g : (S'', s'') \to (S, s)$, and $g' : (S'', s'') \to (S', s')$
such that
\begin{enumerate}
\item $g$ and $g'$ are an open immersion (resp.\ \'etale, smooth, syntomic,
flat and locally of finite presentation) at $s''$,
\item there exists an isomorphism
$$
(S'' \times_{g, S, f} X, \tilde x)
\cong
(S'' \times_{g', S', f'} X', \tilde x')
$$
of germs over the germ $(S'', s'')$ for some choice of points
$\tilde x$ and $\tilde x'$ lying over $(s'', x)$ and $(s'', x')$.
\end{enumerate}
Finally, we simply say that the maps of germs
$f : (X, x) \to (S, s)$ and $f' : (X', x') \to (S', s')$
are {\it flat locally on the base isomorphic} if there exist
$S'', s'', g, g'$ as above but with (1) replaced by
the condition that $g$ and $g'$ are flat at $s''$ (this is
much weaker than any of the $\tau$ conditions above
as a flat morphism need not be open).
\begin{lemma}
\label{lemma-two-fibres}
Let $S$ be a scheme.
Let $(U, R, s, t, c)$ be a groupoid over $S$.
Let $r, r' \in R$ with $t(r) = t(r')$ in $U$.
Set $u = s(r)$, $u' = s(r')$.
Denote $F_u = s^{-1}(u)$ and $F_{u'} = s^{-1}(u')$ the scheme
theoretic fibres.
\begin{enumerate}
\item There exists a common field extension
$\kappa(u) \subset k$, $\kappa(u') \subset k$ and
an isomorphism $(F_u)_k \cong (F_{u'})_k$.
\item We may choose the isomorphism of (1) such that a point
lying over $r$ maps to a point lying over $r'$.
\item If the morphisms $s$, $t$ are flat then the morphisms of germs
$s : (R, r) \to (U, u)$ and $s : (R, r') \to (U, u')$ are flat
locally on the base isomorphic.
\item If the morphisms $s$, $t$ are \'etale
(resp.\ smooth, syntomic, or flat and locally of finite presentation)
then the morphisms of germs $s : (R, r) \to (U, u)$ and
$s : (R, r') \to (U, u')$ are locally on the base isomorphic
in the \'etale (resp.\ smooth, syntomic, or fppf) topology.
\end{enumerate}
\end{lemma}
\begin{proof}
We repeatedly use the properties and the existence of
diagram (\ref{equation-diagram}).
By the properties of the diagram (and
Schemes, Lemma \ref{schemes-lemma-points-fibre-product})
there exists a point $\xi$ of $R \times_{s, U, t} R$
with $\text{pr}_0(\xi) = r$ and $c(\xi) = r'$.
Let $\tilde r = \text{pr}_1(\xi) \in R$.
\medskip\noindent
Proof of (1). Set $k = \kappa(\tilde r)$. Since $t(\tilde r) = u$
and $s(\tilde r) = u'$ we see that $k$ is a common extension
of both $\kappa(u)$ and $\kappa(u')$ and in fact that
both $(F_u)_k$ and $(F_{u'})_k$ are isomorphic to the fibre of
$\text{pr}_1 : R \times_{s, U, t} R \to R$ over $\tilde r$.
Hence (1) is proved.
\medskip\noindent
Part (2) follows since the point $\xi$ maps to $r$, resp.\ $r'$.
\medskip\noindent
Part (3) is clear from the above (using the point $\xi$ for
$\tilde u$ and $\tilde u'$) and the definitions.
\medskip\noindent
If $s$ and $t$ are flat and of finite presentation, then
they are open morphisms (Morphisms, Lemma \ref{morphisms-lemma-fppf-open}).
Hence the image of some affine open neighbourhood $V''$ of $\tilde r$ will
cover an open neighbourhood $V$ of $u$, resp.\ $V'$ of $u'$.
These can be used to show that properties (1) and (2) of the
definition of ``locally on the base isomorphic in the
$\tau$-topology''.
\end{proof}
\section{Cohen-Macaulay presentations}
\label{section-CM}
\noindent
Given any groupoid $(U, R, s, t, c)$ with $s, t$ flat and
locally of finite presentation there exists an ``equivalent''
groupoid $(U', R', s', t', c')$ such that $s'$ and $t'$ are
Cohen-Macaulay morphisms (and locally of finite presentation). See
More on Morphisms, Section \ref{more-morphisms-section-CM}
for more information on Cohen-Macaulay morphisms.
Here ``equivalent'' can be taken to mean that the quotient stacks
$[U/R]$ and $[U'/R']$ are equivalent stacks, see
Groupoids in Spaces, Section \ref{spaces-groupoids-section-stacks}
and Section \ref{spaces-groupoids-section-quotient-stack-restrict}.
\begin{lemma}
\label{lemma-make-CM}
Let $S$ be a scheme.
Let $(U, R, s, t, c)$ be a groupoid over $S$.
Assume $s$ and $t$ are flat and locally of finite presentation.
Then there exists an open $U' \subset U$ such that
\begin{enumerate}
\item $t^{-1}(U') \subset R$ is the largest open subscheme of
$R$ on which the morphism $s$ is Cohen-Macaulay,
\item $s^{-1}(U') \subset R$ is the largest open subscheme of
$R$ on which the morphism $t$ is Cohen-Macaulay,
\item the morphism $t|_{s^{-1}(U')} : s^{-1}(U') \to U$ is
surjective,
\item the morphism $s|_{t^{-1}(U')} : t^{-1}(U') \to U$ is
surjective, and
\item the restriction $R' = s^{-1}(U') \cap t^{-1}(U')$
of $R$ to $U'$ defines a groupoid $(U', R', s', t', c')$ which has the property
that the morphisms $s'$ and $t'$ are Cohen-Macaulay and locally of
finite presentation.
\end{enumerate}
\end{lemma}
\begin{proof}
Apply
Lemma \ref{lemma-local-source}
with
$g = \text{id}$ and
$\mathcal{Q} =$``locally of finite presentation'',
$\mathcal{R} =$``flat and locally of finite presentation'', and
$\mathcal{P}=$``Cohen-Macaulay'', see
Remark \ref{remark-local-source-apply}.
This gives us an open $U' \subset U$ such that
Let $t^{-1}(U') \subset R$ is the largest open subscheme of $R$
on which the morphism $s$ is Cohen-Macaulay.
This proves (1).
Let $i : R \to R$ be the inverse of the groupoid.
Since $i$ is an isomorphism, and $s \circ i = t$ and $t \circ i = s$
we see that $s^{-1}(U')$ is also the largest open of $R$ on which $t$ is
Cohen-Macaulay. This proves (2).
By
More on Morphisms,
Lemma \ref{more-morphisms-lemma-flat-finite-presentation-CM-open}
the open subset $t^{-1}(U')$ is dense in every fibre of $s : R \to U$.
This proves (3). Same argument for (4).
Part (5) is a formal consequence of (1) and (2) and the discussion
of restrictions in
Groupoids, Section \ref{groupoids-section-restrict-groupoid}.
\end{proof}
\section{Restricting groupoids}
\label{section-restricting-groupoids}
\noindent
In this section we collect a bunch of lemmas on
properties of groupoids which are inherited by restrictions.
Most of these lemmas can be proved by contemplating the
defining diagram
\begin{equation}
\label{equation-restriction}
\vcenter{
\xymatrix{
R' \ar[d] \ar[r] \ar@/_3pc/[dd]_{t'} \ar@/^1pc/[rr]^{s'}&
R \times_{s, U} U' \ar[r] \ar[d] &
U' \ar[d]^g \\
U' \times_{U, t} R \ar[d] \ar[r] &
R \ar[r]^s \ar[d]_t &
U \\
U' \ar[r]^g &
U
}
}
\end{equation}
of a restriction. See
Groupoids, Lemma \ref{groupoids-lemma-restrict-groupoid}.
\begin{lemma}
\label{lemma-restrict-preserves-type}
Let $S$ be a scheme.
Let $(U, R, s, t, c)$ be a groupoid scheme over $S$.
Let $g : U' \to U$ be a morphism of schemes.
Let $(U', R', s', t', c')$ be the restriction of
$(U, R, s, t, c)$ via $g$.
\begin{enumerate}
\item If $s, t$ are locally of finite type and $g$ is locally of finite
type, then $s', t'$ are locally of finite type.
\item If $s, t$ are locally of finite presentation and $g$ is locally of finite
presentation, then $s', t'$ are locally of finite presentation.
\item If $s, t$ are flat and $g$ is flat, then $s', t'$ are flat.
\item Add more here.
\end{enumerate}
\end{lemma}
\begin{proof}
The property of being locally of finite type is stable under composition
and arbitrary base change, see
Morphisms, Lemmas \ref{morphisms-lemma-composition-finite-type} and
\ref{morphisms-lemma-base-change-finite-type}.
Hence (1) is clear from Diagram (\ref{equation-restriction}).
For the other cases, see
Morphisms, Lemmas \ref{morphisms-lemma-composition-finite-presentation},
\ref{morphisms-lemma-base-change-finite-presentation},
\ref{morphisms-lemma-composition-flat}, and
\ref{morphisms-lemma-base-change-flat}.
\end{proof}
\noindent
The following lemma could have been used to prove the results of the preceding
lemma in a more uniform way.
\begin{lemma}
\label{lemma-restrict-property}
Let $S$ be a scheme.
Let $(U, R, s, t, c)$ be a groupoid scheme over $S$.
Let $g : U' \to U$ be a morphism of schemes.
Let $(U', R', s', t', c')$ be the restriction of
$(U, R, s, t, c)$ via $g$, and let
$h = s \circ \text{pr}_1 : U' \times_{g, U, t} R \to U$. If
$\mathcal{P}$ is a property of morphisms of schemes such that
\begin{enumerate}
\item $h$ has property $\mathcal{P}$, and
\item $\mathcal{P}$ is preserved under base change,
\end{enumerate}
then $s', t'$ have property $\mathcal{P}$.
\end{lemma}
\begin{proof}
This is clear as $s'$ is the base change of $h$ by
Diagram (\ref{equation-restriction})
and $t'$ is isomorphic to $s'$ as a morphism of schemes.
\end{proof}
\begin{lemma}
\label{lemma-double-restrict}
Let $S$ be a scheme.
Let $(U, R, s, t, c)$ be a groupoid scheme over $S$.
Let $g : U' \to U$ and $g' : U'' \to U'$ be morphisms of schemes.
Set $g'' = g \circ g'$.
Let $(U', R', s', t', c')$ be the restriction of $R$ to $U'$.
Let $h = s \circ \text{pr}_1 : U' \times_{g, U, t} R \to U$,
let $h' = s' \circ \text{pr}_1 : U'' \times_{g', U', t} R \to U'$, and
let $h'' = s \circ \text{pr}_1 : U'' \times_{g'', U, t} R \to U$.
The following diagram is commutative
$$
\xymatrix{
U'' \times_{g', U', t} R' \ar[d]^{h'} &
(U' \times_{g, U, t} R) \times_U (U'' \times_{g'', U, t} R)
\ar[l] \ar[r] \ar[d] &
U'' \times_{g'', U, t} R \ar[d]_{h''} \\
U' &
U' \times_{g, U, t} R \ar[l]_{\text{pr}_0} \ar[r]^h &
U
}
$$
with both squares cartesian where the left upper horizontal arrow
is given by the rule
$$
\begin{matrix}
(U' \times_{g, U, t} R) \times_U (U'' \times_{g'', U, t} R) &
\longrightarrow &
U'' \times_{g', U', t} R' \\
((u', r_0), (u'', r_1)) &
\longmapsto &
(u'', (c(r_1, i(r_0)), (g'(u''), u')))
\end{matrix}
$$
with notation as explained in the proof.
\end{lemma}
\begin{proof}
We work this out by exploiting the functorial point of view
and reducing the lemma to a statement on arrows in restrictions
of a groupoid category. In the last formula of the lemma the
notation $((u', r_0), (u'', r_1))$ indicates a $T$-valued point of
$(U' \times_{g, U, t} R) \times_U (U'' \times_{g'', U, t} R)$.
This means that $u', u'', r_0, r_1$ are $T$-valued points of $U', U'', R, R$
and that $g(u') = t(r_0)$, $g(g'(u'')) = g''(u'') = t(r_1)$, and
$s(r_0) = s(r_1)$. It would be more correct here to write
$g \circ u' = t \circ r_0$ and so on but this makes the notation
even more unreadable. If we think of $r_1$ and $r_0$ as arrows in
a groupoid category then we can represent this by the picture
$$
\xymatrix{
t(r_0) = g(u') &
s(r_0) = s(r_1) \ar[l]_{r_0} \ar[r]^-{r_1} &
t(r_1) = g(g'(u''))
}
$$
This diagram in particular demonstrates that the composition
$c(r_1, i(r_0))$ makes sense. Recall that
$$
R' = R \times_{(t, s), U \times_S U, g \times g} U' \times_S U'
$$
hence a $T$-valued point of $R'$ looks like $(r, (u'_0, u'_1))$
with $t(r) = g(u'_0)$ and $s(r) = g(u'_1)$. In particular given
$((u', r_0), (u'', r_1))$ as above we get the $T$-valued point
$(c(r_1, i(r_0)), (g'(u''), u'))$ of $R'$ because we have
$t(c(r_1, i(r_0))) = t(r_1) = g(g'(u''))$ and
$s(c(r_1, i(r_0))) = s(i(r_0)) = t(r_0) = g(u')$.
We leave it to the reader to show that the left square commutes
with this definition.
\medskip\noindent
To show that the left square is cartesian,
suppose we are given $(v'', p')$ and $(v', p)$ which are $T$-valued points of
$U'' \times_{g', U', t} R'$ and $U' \times_{g, U, t} R$ with
$v' = s'(p')$. This also means that $g'(v'') = t'(p')$ and
$g(v') = t(p)$. By the discussion above we know that we can write
$p' = (r, (u_0', u_1'))$ with $t(r) = g(u'_0)$ and
$s(r) = g(u'_1)$. Using this notation we see that
$v' = s'(p') = u_1'$ and
$g'(v'') = t'(p') = u_0'$. Here is a picture
$$
\xymatrix{
s(p) \ar[r]^-p &
g(v') = g(u'_1) \ar[r]^-r &
g(u'_0) = g(g'(v''))
}
$$
What we have to show is that there exists a unique $T$-valued point
$((u', r_0), (u'', r_1))$ as above such that
$v' = u'$, $p = r_0$, $v'' = u''$ and $p' = (c(r_1, i(r_0)), (g'(u''), u'))$.
Comparing the two diagrams above it is clear that we have no choice
but to take
$$
((u', r_0), (u'', r_1)) = ((v', p), (v'', c(r, p))
$$
Some details omitted.
\end{proof}
\begin{lemma}
\label{lemma-double-restrict-property}
Let $S$ be a scheme.
Let $(U, R, s, t, c)$ be a groupoid scheme over $S$.
Let $g : U' \to U$ and $g' : U'' \to U'$ be morphisms of schemes.
Set $g'' = g \circ g'$.
Let $(U', R', s', t', c')$ be the restriction of $R$ to $U'$.
Let $h = s \circ \text{pr}_1 : U' \times_{g, U, t} R \to U$,
let $h' = s' \circ \text{pr}_1 : U'' \times_{g', U', t} R \to U'$, and
let $h'' = s \circ \text{pr}_1 : U'' \times_{g'', U, t} R \to U$.
Let $\tau \in \{Zariski, \linebreak[0] \etale, \linebreak[0]
smooth, \linebreak[0] syntomic, \linebreak[0] fppf, \linebreak[0] fpqc\}$. Let
$\mathcal{P}$ be a property of morphisms of schemes
which is preserved under base change, and which
is local on the target for the $\tau$-topology. If
\begin{enumerate}
\item $h(U' \times_U R)$ is open in $U$,
\item $\{h : U' \times_U R \to h(U' \times_U R)\}$ is a $\tau$-covering,
\item $h'$ has property $\mathcal{P}$,
\end{enumerate}
then $h''$ has property $\mathcal{P}$. Conversely, if
\begin{enumerate}
\item[(a)] $\{t : R \to U\}$ is a $\tau$-covering,
\item[(d)] $h''$ has property $\mathcal{P}$,
\end{enumerate}
then $h'$ has property $\mathcal{P}$.
\end{lemma}
\begin{proof}
This follows formally from the properties of the diagram of
Lemma \ref{lemma-double-restrict}.
In the first case, note that the image of the morphism
$h''$ is contained in the image of $h$, as $g'' = g \circ g'$.
Hence we may replace the $U$ in the lower right corner of the
diagram by $h(U' \times_U R)$. This explains the significance of
conditions (1) and (2) in the lemma. In the second case, note that
$\{\text{pr}_0 : U' \times_{g, U, t} R \to U'\}$ is a $\tau$-covering
as a base change of $\tau$ and condition (a).
\end{proof}
\section{Properties of groupoids on fields}
\label{section-properties-groupoids-on-fields}
\noindent
A ``groupoid on a field'' indicates a groupoid scheme $(U, R, s, t, c)$
where $U$ is the spectrum of a field. It does {\bf not} mean that
$(U, R, s, t, c)$ is defined over a field, more precisely, it does
{\bf not} mean that the morphisms $s, t : R \to U$ are equal.
Given any field $k$, an abstract group $G$ and a group homomorphism
$\varphi : G \to \text{Aut}(k)$ we obtain a groupoid scheme
$(U, R, s, t, c)$ over $\mathbf{Z}$ by setting
\begin{align*}
U & = \Spec(k) \\
R & = \coprod\nolimits_{g \in G} \Spec(k) \\
s & = \coprod\nolimits_{g \in G} \Spec(\text{id}_k) \\
t & = \coprod\nolimits_{g \in G} \Spec(\varphi(g)) \\
c & = \text{composition in }G
\end{align*}
This example still is a groupoid scheme over $\Spec(k^G)$.
Hence, if $G$ is finite, then $U = \Spec(k)$ is finite over
$\Spec(k^G)$.
In some sense our goal in this section is to show that suitable
finiteness conditions on $s, t$ force any groupoid on a field
to be defined over a finite index subfield $k' \subset k$.
\medskip\noindent
If $k$ is a field and $(G, m)$ is a group scheme over $k$ with structure
morphism $p : G \to \Spec(k)$, then $(\Spec(k), G, p, p, m)$
is an example of a groupoid on a field (and in this case of course the whole
structure is defined over a field). Hence this section can be viewed as the
analogue of
Groupoids, Section \ref{groupoids-section-properties-group-schemes-field}.
\begin{lemma}
\label{lemma-groupoid-on-field-open-multiplication}
Let $S$ be a scheme. Let $(U, R, s, t, c)$ be a groupoid scheme
over $S$. If $U$ is the spectrum of a field, then the composition
morphism $c : R \times_{s, U, t} R \to R$ is open.
\end{lemma}
\begin{proof}
The composition is isomorphic to the projection map
$\text{pr}_1 : R \times_{t, U, t} R \to R$ by
Diagram (\ref{equation-pull}).
The projection is open by
Morphisms, Lemma \ref{morphisms-lemma-scheme-over-field-universally-open}.
\end{proof}
\begin{lemma}
\label{lemma-groupoid-on-field-separated}
Let $S$ be a scheme. Let $(U, R, s, t, c)$ be a groupoid scheme
over $S$. If $U$ is the spectrum of a field,
then $R$ is a separated scheme.
\end{lemma}
\begin{proof}
By
Groupoids, Lemma \ref{groupoids-lemma-group-scheme-over-field-separated}
the stabilizer group scheme $G \to U$ is separated. By
Groupoids, Lemma \ref{groupoids-lemma-diagonal}
the morphism $j = (t, s) : R \to U \times_S U$ is separated.
As $U$ is the spectrum of a field the scheme
$U \times_S U$ is affine (by the construction of fibre products in
Schemes, Section \ref{schemes-section-fibre-products}).
Hence $R$ is a separated scheme, see
Schemes, Lemma \ref{schemes-lemma-separated-permanence}.
\end{proof}
\begin{lemma}
\label{lemma-groupoid-on-field-homogeneous}
Let $S$ be a scheme. Let $(U, R, s, t, c)$ be a groupoid scheme
over $S$. Assume $U = \Spec(k)$ with $k$ a field.
For any points $r, r' \in R$ there exists a field extension
$k \subset k'$ and points
$r_1, r_2 \in R \times_{s, \Spec(k)} \Spec(k')$
and a diagram
$$
\xymatrix{
R &
R \times_{s, \Spec(k)} \Spec(k')
\ar[l]_-{\text{pr}_0} \ar[r]^\varphi &
R \times_{s, \Spec(k)} \Spec(k')
\ar[r]^-{\text{pr}_0} &
R
}
$$
such that $\varphi$ is an isomorphism of schemes over $\Spec(k')$,
we have $\varphi(r_1) = r_2$, $\text{pr}_0(r_1) = r$, and
$\text{pr}_0(r_2) = r'$.
\end{lemma}
\begin{proof}
This is a special case of
Lemma \ref{lemma-two-fibres}
parts (1) and (2).
\end{proof}
\begin{lemma}
\label{lemma-restrict-groupoid-on-field}
Let $S$ be a scheme. Let $(U, R, s, t, c)$ be a groupoid scheme
over $S$. Assume $U = \Spec(k)$ with $k$ a field.
Let $k \subset k'$ be a field extension, $U' = \Spec(k')$
and let $(U', R', s', t', c')$ be the restriction of
$(U, R, s, t, c)$ via $U' \to U$. In the defining diagram
$$
\xymatrix{
R' \ar[d] \ar[r] \ar@/_3pc/[dd]_{t'} \ar@/^1pc/[rr]^{s'} \ar@{..>}[rd] &
R \times_{s, U} U' \ar[r] \ar[d] &
U' \ar[d] \\
U' \times_{U, t} R \ar[d] \ar[r] &
R \ar[r]^s \ar[d]_t &
U \\
U' \ar[r] &
U
}
$$
all the morphisms are surjective, flat, and universally open.
The dotted arrow $R' \to R$ is in addition affine.
\end{lemma}
\begin{proof}
The morphism $U' \to U$ equals $\Spec(k') \to \Spec(k)$,
hence is affine, surjective and flat. The morphisms $s, t : R \to U$
and the morphism $U' \to U$ are universally open by
Morphisms, Lemma \ref{morphisms-lemma-scheme-over-field-universally-open}.
Since $R$ is not empty and $U$ is the spectrum of a field the morphisms
$s, t : R \to U$ are surjective and flat. Then you conclude by using
Morphisms, Lemmas \ref{morphisms-lemma-base-change-surjective},
\ref{morphisms-lemma-composition-surjective},
\ref{morphisms-lemma-composition-open},
\ref{morphisms-lemma-base-change-affine},
\ref{morphisms-lemma-composition-affine},
\ref{morphisms-lemma-base-change-flat}, and
\ref{morphisms-lemma-composition-flat}.
\end{proof}
\begin{lemma}
\label{lemma-groupoid-on-field-explain-points}
Let $S$ be a scheme. Let $(U, R, s, t, c)$ be a groupoid scheme
over $S$. Assume $U = \Spec(k)$ with $k$ a field.
For any point $r \in R$ there exist
\begin{enumerate}
\item a field extension $k \subset k'$ with $k'$ algebraically closed,
\item a point $r' \in R'$ where $(U', R', s', t', c')$ is the
restriction of $(U, R, s, t, c)$ via $\Spec(k') \to \Spec(k)$
\end{enumerate}
such that
\begin{enumerate}
\item the point $r'$ maps to $r$ under the morphism $R' \to R$, and
\item the maps $s', t' : R' \to \Spec(k')$ induce isomorphisms
$k' \to \kappa(r')$.
\end{enumerate}
\end{lemma}
\begin{proof}
Translating the geometric statement into a statement on fields,
this means that we can find a diagram
$$
\xymatrix{
k' & k' \ar[l]^1 & \\
k' \ar[u]^\tau & \kappa(r) \ar[lu]^\sigma & k \ar[l]^-s \ar[lu]_i \\
& k \ar[lu]^i \ar[u]_t
}
$$
where $i : k \to k'$ is the embedding of $k$ into $k'$,
the maps $s, t : k \to \kappa(r)$ are induced by $s, t : R \to U$, and
the map $\tau : k' \to k'$ is an automorphism. To produce such
a diagram we may proceed in the following way:
\begin{enumerate}
\item Pick $i : k \to k'$ a field map with $k'$ algebraically closed of
very large transcendence degree over $k$.
\item Pick an embedding $\sigma : \kappa(r) \to k'$ such that
$\sigma \circ s = i$. Such a $\sigma$ exists because we can just
choose a transcendence basis $\{x_\alpha\}_{\alpha \in A}$ of $\kappa(r)$
over $k$ and find $y_\alpha \in k'$, $\alpha \in A$ which are algebraically
independent over $i(k)$, and map $s(k)(\{x_\alpha\})$ into $k'$ by
the rules $s(\lambda) \mapsto i(\lambda)$ for $\lambda \in k$
and $x_\alpha \mapsto y_\alpha$ for $\alpha \in A$.