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_950.java
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package com.fishercoder.solutions;
import java.util.ArrayDeque;
import java.util.Arrays;
import java.util.Deque;
/**
* 950. Reveal Cards In Increasing Order
*
* In a deck of cards, every card has a unique integer. You can order the deck in any order you want.
* Initially, all the cards start face down (unrevealed) in one deck.
* Now, you do the following steps repeatedly, until all cards are revealed:
* Take the top card of the deck, reveal it, and take it out of the deck.
* If there are still cards in the deck, put the next top card of the deck at the bottom of the deck.
* If there are still unrevealed cards, go back to step 1. Otherwise, stop.
* Return an ordering of the deck that would reveal the cards in increasing order.
*
* The first entry in the answer is considered to be the top of the deck.
*
* Example 1:
* Input: [17,13,11,2,3,5,7]
* Output: [2,13,3,11,5,17,7]
*
* Explanation:
* We get the deck in the order [17,13,11,2,3,5,7] (this order doesn't matter), and reorder it.
* After reordering, the deck starts as [2,13,3,11,5,17,7], where 2 is the top of the deck.
* We reveal 2, and move 13 to the bottom. The deck is now [3,11,5,17,7,13].
* We reveal 3, and move 11 to the bottom. The deck is now [5,17,7,13,11].
* We reveal 5, and move 17 to the bottom. The deck is now [7,13,11,17].
* We reveal 7, and move 13 to the bottom. The deck is now [11,17,13].
* We reveal 11, and move 17 to the bottom. The deck is now [13,17].
* We reveal 13, and move 17 to the bottom. The deck is now [17].
* We reveal 17.
* Since all the cards revealed are in increasing order, the answer is correct.
*
* Note:
* 1 <= A.length <= 1000
* 1 <= A[i] <= 10^6
* A[i] != A[j] for all i != j
*/
public class _950 {
public static class Solution1 {
public int[] deckRevealedIncreasing(int[] deck) {
Arrays.sort(deck);
Deque<Integer> deque = new ArrayDeque<>();
for (int i = deck.length - 1; i >= 0; i--) {
if (i != deck.length - 1) {
deque.addFirst(deque.pollLast());
}
deque.addFirst(deck[i]);
}
int[] result = new int[deck.length];
int i = 0;
while (!deque.isEmpty()) {
result[i++] = deque.pollFirst();
}
return result;
}
}
}