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请问为什么在开启gost api使用gost-ui的时候,实时运行的命令行不会显示在ui中呢? #2

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FOXCOOO opened this issue Jul 10, 2024 · 2 comments

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@FOXCOOO
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FOXCOOO commented Jul 10, 2024

比如,先执行了 gost -api :18080

然后再执行了 gost -L tcp://:10001 -F relay+wss://xx.xx.xx.xx:20001

gost-ui的service和chain并不会显示任何,下面的完整配置也一样

但是在控制台使用 gost -O json 输出配置文件的时候,显示完全

因为毕竟命令行新建转发或者其他服务的时候要比修改配置文件要简单许多。新建之后,然后在web-ui统一管理。

@cnwhy
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cnwhy commented Jul 25, 2024

现在情况应该是只有用web-api启动的服务会在才会出现在web-api的数据中;
gost -L tcp://:10001 -F relay+wss://xx.xx.xx.xx:20001 这种用命令行启动的服务,和web-api是没有关联的

@yangguangwuwu
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yangguangwuwu commented Sep 3, 2024

应该是不能分开执行
gost -api :18080 -L tcp://:10001 -F relay+wss://xx.xx.xx.xx:20001

https://gost.run/tutorials/api/overview/#__tabbed_2_2 数据估计在上下文中存 每个命令上下文不一样

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