Can't absolute paths be used in the ffmpeg.run method

[syjf]

Can't it be written like this
ffmpeg.run('-i' , 'http://127.0.0.1:5001/upload/202406/11dc85da-4937-473e-9e79-d193bf83902d.mp4'.......)
Can we only do this
ffmpeg.FS(
"writeFile",
"video",
await fetchFile(
"http:xxxx.mp4"
)
)
ffmpeg.run('-i' , 'video'.......)

[syjf]

If you write the address directly, an error message will appear, prompting WebSocket connection to 'ws://127.0.0.1:5001/' failed: Error during WebSocket handshake: Unexpected response code: 200
Is there anything to configure

[syjf]

Why call WebSocket
Do you just want to request resources