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I think that the optimal selection algorithm would minimize the sum of the
errors of each slice. If that were true, one implementation would be this:
1. If there are no slices left to fill, exit.
2. Fill all slices with their best images, allowing duplicates.
3. Of all the cells that used duplicate images, only keep the one with the
lowest error, throw the rest out.
4. Go to step 1.
Original issue reported on code.google.com by brianfromoregon on 1 Jun 2010 at 11:30
The text was updated successfully, but these errors were encountered:
I tested out a couple of implementations found here:
http://timefinder.svn.sourceforge.net/viewvc/timefinder/trunk/timefinder-
algo/src/main/java/de/timefinder/algo/roomassignment/
They don't practically scale well to n=thousands, too slow. Googling shows a
few
papers on monte carlo based approximation algorithms which may be the best bet.
Original comment by brianfromoregon on 5 Jun 2010 at 4:21
Another way of stating the problem: given a MxN weighted-edge biclique, find a
minimal assignment (as in the assignment problem).
I hope there's an approximation solution, maybe using monte-carlo simulations.
Original comment by brianfromoregon on 25 Jun 2010 at 2:07
Original issue reported on code.google.com by
brianfromoregon
on 1 Jun 2010 at 11:30The text was updated successfully, but these errors were encountered: