concatenation_of_array.py

# Given an integer array nums of length n, you want to create an array ans of length 2n where ans[i] == nums[i] and ans[i + n]
# == nums[i] for 0 <= i < n (0-indexed).

# Specifically, ans is the concatenation of two nums arrays.

# Return the array ans.

 

# Example 1:

# Input: nums = [1,2,1]
# Output: [1,2,1,1,2,1]
# Explanation: The array ans is formed as follows:
# - ans = [nums[0],nums[1],nums[2],nums[0],nums[1],nums[2]]
# - ans = [1,2,1,1,2,1]
# Example 2:

# Input: nums = [1,3,2,1]
# Output: [1,3,2,1,1,3,2,1]
# Explanation: The array ans is formed as follows:
# - ans = [nums[0],nums[1],nums[2],nums[3],nums[0],nums[1],nums[2],nums[3]]
# - ans = [1,3,2,1,1,3,2,1]
 

# Constraints:

# n == nums.length
# 1 <= n <= 1000
# 1 <= nums[i] <= 1000

class Solution:
    def getConcatenation(self, nums: List[int]) -> List[int]:
        return nums + nums