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DirectedCycle.java
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/**
* The {@code DirectedCycle} class represents a data type for
* determining whether a digraph has a directed cycle.
* The <em>hasCycle</em> operation determines whether the digraph has
* a directed cycle and, and of so, the <em>cycle</em> operation
* returns one.
* <p>
* This implementation uses depth-first search.
* The constructor takes time proportional to <em>V</em> + <em>E</em>
* (in the worst case),
* where <em>V</em> is the number of vertices and <em>E</em> is the number of edges.
* Afterwards, the <em>hasCycle</em> operation takes constant time;
* the <em>cycle</em> operation takes time proportional
* to the length of the cycle.
* <p>
* See {@link Topological} to compute a topological order if the
* digraph is acyclic.
* <p>
* For additional documentation,
* see <a href="http://algs4.cs.princeton.edu/42digraph">Section 4.2</a> of
* <i>Algorithms, 4th Edition</i> by Robert Sedgewick and Kevin Wayne.
*
* @author Robert Sedgewick
* @author Kevin Wayne
*/
import edu.princeton.cs.algs4.*;
public class DirectedCycle {
private boolean[] marked; // marked[v] = has vertex v been marked?
private int[] edgeTo; // edgeTo[v] = previous vertex on path to v
private boolean[] onStack; // onStack[v] = is vertex on the stack?
private Stack<Integer> cycle; // directed cycle (or null if no such cycle)
/**
* Determines whether the digraph {@code G} has a directed cycle and, if so,
* finds such a cycle.
* @param G the digraph
*/
public DirectedCycle(Digraph G) {
marked = new boolean[G.V()];
onStack = new boolean[G.V()];
edgeTo = new int[G.V()];
for (int v = 0; v < G.V(); v++)
if (!marked[v] && cycle == null) dfs(G, v);
}
// check that algorithm computes either the topological order or finds a directed cycle
private void dfs(Digraph G, int v) {
onStack[v] = true;
marked[v] = true;
for (int w : G.adj(v)) {
// short circuit if directed cycle found
if (cycle != null) return;
// found new vertex, so recur
else if (!marked[w]) {
edgeTo[w] = v;
dfs(G, w);
}
// trace back directed cycle
else if (onStack[w]) {
cycle = new Stack<Integer>();
for (int x = v; x != w; x = edgeTo[x]) {
cycle.push(x);
}
cycle.push(w);
cycle.push(v);
assert check();
}
}
onStack[v] = false;
}
/**
* Does the digraph have a directed cycle?
* @return {@code true} if the digraph has a directed cycle, {@code false} otherwise
*/
public boolean hasCycle() {
return cycle != null;
}
/**
* Returns a directed cycle if the digraph has a directed cycle, and {@code null} otherwise.
* @return a directed cycle (as an iterable) if the digraph has a directed cycle,
* and {@code null} otherwise
*/
public Iterable<Integer> cycle() {
return cycle;
}
// certify that digraph has a directed cycle if it reports one
private boolean check() {
if (hasCycle()) {
// verify cycle
int first = -1, last = -1;
for (int v : cycle()) {
if (first == -1) first = v;
last = v;
}
if (first != last) {
System.err.printf("cycle begins with %d and ends with %d\n", first, last);
return false;
}
}
return true;
}
/**
* Unit tests the {@code DirectedCycle} data type.
*
* @param args the command-line arguments
*/
public static void main(String[] args) {
In in = new In(args[0]);
Digraph G = new Digraph(in);
DirectedCycle finder = new DirectedCycle(G);
if (finder.hasCycle()) {
StdOut.print("Directed cycle: ");
for (int v : finder.cycle()) {
StdOut.print(v + " ");
}
StdOut.println();
}
else {
StdOut.println("No directed cycle");
}
StdOut.println();
}
}