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Help with the plotCV2() function #2
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Hi there, Do you get the desired output regardless of the warning? warning comes from package dependencies. As long as you get the output you wish, those warnings, which are plotting related, could be ignored. Please consider our latest tutorials on the reproducibility repo. |
Hello, After the warnings I got the plot and table, but without outliers. I managed to get them only after running the source code. This is the link to the manual (I am at the very beginning, p.6-7): https://github.com/soroorh/proteomicscasestudies/blob/master/msImputeUsersGuide.pdf Thank you very much for your help! |
correct - it is more for data exploration, and is not incorporated into any modelling steps of msImpute or DE fitting e.g. using limma. The document you're looking at is outdated, i'm afraid. Latest tutorials are here Could you please provide your |
Clear, thank you very much for the details and link.
Thank you for your support :) |
Hey. Sorry about the delay - Line 29 in 07867d1
Hope this helps! |
Hi, |
no worries! happy to help! |
Hello,
I am new here. I am trying the pkg 'msImpute' to hopefully use it in some analyses.
I am following both the vignette and the user manual. In the latter one, I arrived at the mean-CV^2 evaluation. The function
plotCV2()
, should show on the plot the outliers. In the manual, this is the code:Extracting the data from the object
peptideCV2
, a column with RBF kernels and outliers should be present.However, running this code, I got a plot without outliers and a table without RBF kernels and outliers columns.
I checked the source code from here: https://rdrr.io/bioc/msImpute/src/R/plotCV2.R
I saw that the argument
outlier
is set to FALSE by default. I tried again changing it:At this point, I got a warning message:
I don't understand what happened.
Finally, I tried running the source code for the function, and then again:
peptideCV2 <- plotCV2(y, trend = FALSE, outlier = TRUE)
I got the right plot and table, as in the manual.
Am I doing something wrong?
Thank you for any help.
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